\[ \frac{-3-5x}{9} = \frac{-5+9x}{15} \]
\[ \frac{-3-5x}{9} \times 45 = \frac{-5+9x}{15} \times 45 \]
\[ (-3-5x) \times 5 = (-5+9x) \times 3 \]\[ -15 - 25x = -15 + 27x \]
\[ -25x - 27x = -15 + 15 \]
\[ -52x = 0 \]\[ x = \frac{0}{-52} \]
\[ x = 0 \]Ответ: 0