Контрольные задания > Prove that if x + y = 1, then $$\frac{x}{y^3 - 1} - \frac{y}{x^3 - 1} = \frac{2(y - x)}{x^2y^2 + 3}$$

Вопрос:

Prove that if x + y = 1, then $$\frac{x}{y^3 - 1} - \frac{y}{x^3 - 1} = \frac{2(y - x)}{x^2y^2 + 3}$$

Ответ:

I am unable to solve the math problem or prove that equation at the moment.

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