\(\frac{3}{25}+\frac{16}{25}=\frac{19}{25}\).
- При \(a=\frac{1}{25}\): \(\frac{19}{25}-\frac{1}{25}=\frac{18}{25}\).
- При \(a=\frac{3}{25}\): \(\frac{19}{25}-\frac{3}{25}=\frac{16}{25}\).
- При \(a=\frac{7}{25}\): \(\frac{19}{25}-\frac{7}{25}=\frac{12}{25}\).
Ответ: \(\frac{18}{25};\ \frac{16}{25};\ \frac{12}{25}\).