Ответ:

\[\frac{3}{25}+\frac{16}{25}-a=\frac{19}{25}-a.\]

  1. \(a=\frac{1}{25}\): \(\frac{19}{25}-\frac{1}{25}=\frac{18}{25}\).
  2. \(a=\frac{3}{25}\): \(\frac{19}{25}-\frac{3}{25}=\frac{16}{25}\).
  3. \(a=\frac{7}{25}\): \(\frac{19}{25}-\frac{7}{25}=\frac{12}{25}\).

Ответ: а) \(\frac{18}{25}\); б) \(\frac{16}{25}\); в) \(\frac{12}{25}\).