Решение:
\begin{aligned}
\frac{2}{3}(\frac{6}{7}y) + (\frac{2}{7} + y) &= \frac{2}{3} \cdot \frac{6}{7}y + \frac{2}{3} \cdot \frac{2}{7} + \frac{2}{3}y \\
&= \frac{4}{7}y + \frac{4}{21} + \frac{2}{3}y \\
&= (\frac{4}{7} + \frac{2}{3})y + \frac{4}{21} \\
&= (\frac{12}{21} + \frac{14}{21})y + \frac{4}{21} \\
&= \frac{26}{21}y + \frac{4}{21}
\end{aligned}
Подставим y = 3:
\[\frac{26}{21} \cdot 3 + \frac{4}{21} = \frac{78}{21} + \frac{4}{21} = \frac{82}{21} = 3\frac{19}{21}\]
Ответ: \(\frac{82}{21}\) или \(3\frac{19}{21}\)