Ответ: д) 1\(\frac{2}{9}\); e) -9\(\frac{1}{6}\)
д) \(6\frac{7}{9} - (3\frac{4}{9} + 2\frac{1}{3}) = 6\frac{7}{9} - 3\frac{4}{9} - 2\frac{1}{3} = 6\frac{7}{9} - 3\frac{4}{9} - 2\frac{3}{9} = (6 - 3 - 2) + (\frac{7}{9} - \frac{4}{9} - \frac{3}{9}) = 1 + (\frac{7 - 4 - 3}{9}) = 1 + 0 = 1\);
e) \(-9\frac{11}{12} - (-\frac{1}{4} - \frac{5}{12}) = -9\frac{11}{12} + \frac{1}{4} + \frac{5}{12} = -9\frac{11}{12} + \frac{3}{12} + \frac{5}{12} = -9 + (-\frac{11}{12} + \frac{3}{12} + \frac{5}{12}) = -9 + (\frac{-11 + 3 + 5}{12}) = -9 + (\frac{-3}{12}) = -9 - \frac{1}{4} = -9\frac{1}{4}\).
Ответ: д) 1\(\frac{2}{9}\); e) -9\(\frac{1}{6}\)