Ответ:

  1. НОЗ(8, 6, 9, 4) = 72. Получаем: \(\frac{3}{8}=\frac{27}{72}\), \(\frac{5}{6}=\frac{60}{72}\), \(\frac{7}{9}=\frac{56}{72}\), \(\frac{1}{4}=\frac{18}{72}\). Следовательно, \(\frac{1}{4}<\frac{3}{8}<\frac{7}{9}<\frac{5}{6}\).
  2. НОЗ(9, 15, 45, 30) = 90. Получаем: \(\frac{4}{9}=\frac{40}{90}\), \(\frac{7}{15}=\frac{42}{90}\), \(\frac{23}{45}=\frac{46}{90}\), \(\frac{13}{30}=\frac{39}{90}\). Следовательно, \(\frac{13}{30}<\frac{4}{9}<\frac{7}{15}<\frac{23}{45}\).