3. Расставь знаки арифметических действий и, возможно, скобки, между числами 1, 2, 3, 4, 5 (именно в таком порядке), чтобы значение полученного выражения оказалось максимальным.

1 + 2 × 3 × 4 × 5 = 1 + 120 = 121

(1 + 2) × 3 × 4 × 5 = 3 × 3 × 4 × 5 = 9 × 20 = 180

(1 + 2 + 3) × 4 × 5 = 6 × 4 × 5 = 24 × 5 = 120

(1 + 2) × (3 + 4) × 5 = 3 × 7 × 5 = 21 × 5 = 105

1 × 2 + 3 × 4 × 5 = 2 + 60 = 62

1 + 2 + 3 + 4 × 5 = 6 + 20 = 26

1 × 2 × 3 × 4 + 5 = 24 + 5 = 29

(1 × 2 × 3 × 4) × 5 = 24 × 5 = 120

1 × 2 × 3 + 4 × 5 = 6 + 20 = 26

1 × (2 + 3) × 4 × 5 = 1 × 5 × 4 × 5 = 20 × 5 = 100

1 + (2 × 3 + 4) × 5 = 1 + (6 + 4) × 5 = 1 + 10 × 5 = 1 + 50 = 51

1 × 2 × (3 + 4 + 5) = 2 × 12 = 24

1 × (2 + 3 + 4 + 5) = 1 × 14 = 14

1 + 2 × (3 + 4 + 5) = 1 + 2 × 12 = 1 + 24 = 25

1 × 2 + (3 + 4) × 5 = 2 + 7 × 5 = 2 + 35 = 37

(1 + 2 + 3 + 4 + 5) = 15

1 + 2 × 3 + 4 × 5 = 1 + 6 + 20 = 27

(1 + 2 + 3 + 4) × 5 = 10 × 5 = 50

1 × 2 × (3 + 4) × 5 = 2 × 7 × 5 = 70

1 × 2 + 3 + 4 + 5 = 2 + 3 + 4 + 5 = 14

1 × (2 × 3 + 4 + 5) = 1 × (6 + 4 + 5) = 15

1 × 2 × 3 + 4 + 5 = 6 + 4 + 5 = 15

(1 + 2 + 3 + 4) × 5 = 10 × 5 = 50

1 × (2 + 3) + 4 × 5 = 5 + 20 = 25

(1 × 2 × 3 + 4) × 5 = (6 + 4) × 5 = 10 × 5 = 50

1 × (2 + 3 + 4) × 5 = 1 × 9 × 5 = 45

1 + (2 + 3) × 4 × 5 = 1 + 5 × 4 × 5 = 1 + 100 = 101

1 + 2 + (3 + 4) × 5 = 1 + 2 + 7 × 5 = 3 + 35 = 38

1 + 2 + 3 × (4 + 5) = 1 + 2 + 3 × 9 = 3 + 27 = 30

1 × (2 + 3) × (4 + 5) = 1 × 5 × 9 = 45

(1 + 2) × 3 × 4 × 5 = 3 × 3 × 4 × 5 = 9 × 20 = 180

(1 + 2 + 3) × 4 × 5 = 6 × 4 × 5 = 24 × 5 = 120

1 × 2 × 3 × 4 × 5 = 120

1 + 2 × 3 × 4 × 5 = 121

Ответ: (1 + 2) × 3 × 4 × 5 = 180