Разложите на множители квадратный трехчлен: 6x^2+5x-4.

\[6x^{2} + 5x - 4 =\]

\[= 6 \cdot \left( x - \frac{1}{2} \right)\left( x + \frac{4}{3} \right) =\]

\[= (2x - 1)(3x + 4)\]

\[6x^{2} + 5x - 4 = 0\]

\[D = 25 + 96 = 121\]

\[x_{1} = \frac{- 5 + 11}{12} = \frac{6}{12} = \frac{1}{2};\ \ \ \]

\[x_{2} = \frac{- 5 - 11}{12} = - \frac{16}{12} = - \frac{4}{3}\]