a) $$b^3-2b^2+b = b(b^2 - 2b + 1) = b(b-1)^2$$
б) $$ab^3+2a^2b^2+a^3b = ab(b^2 + 2ab + a^2) = ab(b+a)^2$$
в) $$3a+3b-ax-bx = 3(a+b) - x(a+b) = (a+b)(3-x)$$
г) $$5a-b+5a^2-ab = 5a - b + a(5a - b) = (5a-b)(1+a)$$
д) $$7a-7b+2b^2-2ab = 7(a-b) - 2b(a-b) = (a-b)(7-2b)$$
**Ответ:**
a) $$b(b-1)^2$$
б) $$ab(b+a)^2$$
в) $$(a+b)(3-x)$$
г) $$(5a-b)(1+a)$$
д) $$(a-b)(7-2b)$$