8. Решить уравнение tg (x-$$\frac{\pi}{6}$$) = -$$\frac{\sqrt{3}}{2}$$
$$tg (x-\frac{\pi}{6}) = -\frac{\sqrt{3}}{2}$$
$$x-\frac{\pi}{6} = arctg(-\frac{\sqrt{3}}{2}) + \pi n, n \in Z$$
$$x = arctg(-\frac{\sqrt{3}}{2}) + \frac{\pi}{6} + \pi n, n \in Z$$
$$x = -arctg(\frac{\sqrt{3}}{2}) + \frac{\pi}{6} + \pi n, n \in Z$$
Ответ: $$x = -arctg(\frac{\sqrt{3}}{2}) + \frac{\pi}{6} + \pi n, n \in Z$$