Решить задание 2: Даны комплексные числа $$z_1 = 2 + i$$, $$z_2 = 3i + 1$$, $$z_3 = -2 - i$$. Вычислите: a) $$z_1 + z_2$$, б) $$z_1 + z_3$$, в) $$z_1 - z_2$$, г) $$z_2 - z_3$$, д) $$z_1 * z_2$$, e) $$z_3 * z_2$$.

a) $$z_1 + z_2 = (2 + i) + (1 + 3i) = (2 + 1) + (i + 3i) = 3 + 4i$$

б) $$z_1 + z_3 = (2 + i) + (-2 - i) = (2 - 2) + (i - i) = 0$$

в) $$z_1 - z_2 = (2 + i) - (1 + 3i) = (2 - 1) + (i - 3i) = 1 - 2i$$

г) $$z_2 - z_3 = (1 + 3i) - (-2 - i) = (1 + 2) + (3i + i) = 3 + 4i$$

д) $$z_1 * z_2 = (2 + i) * (1 + 3i) = 2 * 1 + 2 * 3i + i * 1 + i * 3i = 2 + 6i + i + 3i^2 = 2 + 7i - 3 = -1 + 7i$$

e) $$z_3 * z_2 = (-2 - i) * (1 + 3i) = -2 * 1 - 2 * 3i - i * 1 - i * 3i = -2 - 6i - i - 3i^2 = -2 - 7i + 3 = 1 - 7i$$

**Ответы:**

* **a) $$3 + 4i$$**
* **б) $$0$$**
* **в) $$1 - 2i$$**
* **г) $$3 + 4i$$**
* **д) $$-1 + 7i$$**
* **e) $$1 - 7i$$**