Решите графически уравнение -x^2+3x+4=0.

Question

Accepted Answer

\[- x^{2} + 3x + 4 = 0\]

\[y = - x^{2} + 3x + 4\]

\[x_{b} = - \frac{b}{2a} = \frac{- 3}{- 2} = 1,5\]

\[y_{b} = - 2,25 + 4,5 + 4 = 6,25\]

\[x\]	\[- 1\]	\[0\]	\[1,5\]	\[3\]	\[4\]
\[y\]	\[0\]	\[4\]	\[6,25\]	\[4\]	\[0\]

\[Ответ:\ - 1;4.\]