Решите линейное уравнение: -1/3 (6 - 0,2x + 4/5 (2x - 1,2)) - x + 2 =

Решим уравнение:

$$-\frac{1}{3}(6 - 0,2x + \frac{4}{5}(2x - 1,2)) - x + 2 = 0$$

$$-\frac{1}{3}(6 - 0,2x + \frac{8}{5}x - \frac{4,8}{5}) - x + 2 = 0$$

$$-\frac{1}{3}(6 - 0,2x + 1,6x - 0,96) - x + 2 = 0$$

$$-\frac{1}{3}(5,04 + 1,4x) - x + 2 = 0$$

$$-\frac{5,04}{3} - \frac{1,4x}{3} - x + 2 = 0$$

$$-1,68 - \frac{1,4}{3}x - x + 2 = 0$$

$$0,32 - \frac{4,4}{3}x = 0$$

$$\frac{4,4}{3}x = 0,32$$

$$x = \frac{0,32 \cdot 3}{4,4} = \frac{0,96}{4,4} = \frac{96}{440} = \frac{24}{110} = \frac{12}{55}$$

$$x = \frac{12}{55}$$

Ответ: 12/55