Решите неравенство: |x+1|<=3,1.

\[|x + 1| \leq 3,1\]

\[- 3,1 \leq x + 1 \leq 3,1\]

\[- 4,1 \leq x \leq 2,1\]

\[Ответ:\ \lbrack - 4,1;2,1\rbrack.\]