Решите неравенство: (2x^2)/(x-4)>(-32)/(4-x).

\[\frac{2x^{2}}{x - 4} > \frac{- 32}{4 - x}\]

\[\frac{2x^{2}}{x - 4} > \frac{32}{x - 4}\]

\[\frac{2x^{2} - 32}{x - 4} > 0\]

\[\frac{2 \cdot \left( x^{2} - 16 \right)}{x - 4} > 0\]

\[\frac{2 \cdot (x - 4)(x + 4)}{x - 4} > 0\]

\[Ответ:( - 4;4) \cup (4; + \infty).\]