Решите неравенство: (x^2+x-12)/(x-3)>0.

\[\frac{x^{2} + x - 12}{x - 3} > 0\]

\[\frac{(x - 3)(x + 4)}{x - 3} > 0\]

\[Ответ:( - 4;3) \cup (3; + \infty).\]