Решите неравенство: (x+1)(x-4)(3x-6)<0.

\[(x + 1)(x - 4)(3x - 6) < 0\]

\[3 \cdot \left( x - ( - 1) \right)(x - 4)(x - 2) < 0\]

\[Ответ:( - \infty; - 1) \cup (2;4).\]