Решите неравенство: (x^2+4)(x+4)(x-8)<=0.

\[\left( x^{2} + 4 \right)(x + 4)(x - 8) \leq 0\]

\[x^{2} + 4 \geq 0;\]

\[(x + 4)(x - 8) \leq 0\]

\[- 4 \leq x \leq 8.\]