Решите неравенство: x^2+6x+5>0.

\[x^{2} + 6x + 5 > 0\]

\[D = 6^{2} - 4 \cdot 1 \cdot 5 =\]

\[= 36 - 20 = 16\]

\[x_{1} = \frac{- 6 + \sqrt{16}}{2 \cdot 1} = \frac{- 6 + 4}{2} =\]

\[= - \frac{2}{2} = - 1;\ \ \ \ \ \]

\[x_{2} = \frac{- 6 - \sqrt{16}}{2 \cdot 1} = \frac{- 6 - 4}{2} =\]

\[= - \frac{10}{2} = - 5\]

\[Ответ:( - \infty; - 5) \cup ( - 1; + \infty).\]