Решите неравенство: (x^2+x-6)(x^2-6x+8)<0.

Question

\[\left( x^{2} + x - 6 \right)\left( x^{2} - 6x + 8 \right) < 0\]

\[(x - 2)^{2}(x + 3)(x - 4) < 0\]

\[Ответ:( - 3;2) \cup (2;4).\]

Accepted Answer

\[\left( x^{2} + x - 6 \right)\left( x^{2} - 6x + 8 \right) < 0\]

\[(x - 2)^{2}(x + 3)(x - 4) < 0\]

\[Ответ:( - 3;2) \cup (2;4).\]