Решите неравенство: (x^2-3x-4)/(x-4)>0.

Question

\[\frac{x^{2} - 3x - 4}{x - 4} > 0\]

\[\frac{(x - 4)(x + 1)}{x - 4} > 0\]

\[Ответ:( - 1;4) \cup (4; + \infty).\]

Accepted Answer

\[\frac{x^{2} - 3x - 4}{x - 4} > 0\]

\[\frac{(x - 4)(x + 1)}{x - 4} > 0\]

\[Ответ:( - 1;4) \cup (4; + \infty).\]