\[\frac{x - 3}{3 - x} \leq \frac{1}{6}\]
\[- \left( \frac{x - 3}{x - 3} \right) \leq \frac{1}{6}\]
\[x eq 3,\ \ - 1 < \frac{1}{6}\]
\[Ответ:( - \infty;\ 3) \cup (3;\ + \infty).\]