Решите неравенство: (x-3)(x^2-2x+8)>(x-3)(x^2+x-4).

\[(x - 3)( - 3x + 12) > 0\]

\[- 3 \cdot (x - 3)(x - 4) > 0\]

\[(x - 3)(x - 4) < 0\]

\[Ответ:\ \ (3;4).\]