Решите примеры: $$3\frac{7}{8}+7\frac{1}{2} =$$ $$8\frac{3}{40}+7\frac{1}{2} =$$ $$5\frac{1}{12}+3\frac{7}{32} =$$ $$9\frac{1}{8}+9\frac{5}{12} =$$

Решим каждый пример по отдельности:

1) $$3\frac{7}{8}+7\frac{1}{2} = 3\frac{7}{8}+7\frac{4}{8} = (3+7) + (\frac{7}{8}+\frac{4}{8}) = 10 + \frac{11}{8} = 10 + 1\frac{3}{8} = 11\frac{3}{8}$$

2) $$8\frac{3}{40}+7\frac{1}{2} = 8\frac{3}{40}+7\frac{20}{40} = (8+7) + (\frac{3}{40}+\frac{20}{40}) = 15 + \frac{23}{40} = 15\frac{23}{40}$$

3) $$5\frac{1}{12}+3\frac{7}{32} = 5\frac{8}{96}+3\frac{21}{96} = (5+3) + (\frac{8}{96}+\frac{21}{96}) = 8 + \frac{29}{96} = 8\frac{29}{96}$$

4) $$9\frac{1}{8}+9\frac{5}{12} = 9\frac{3}{24}+9\frac{10}{24} = (9+9) + (\frac{3}{24}+\frac{10}{24}) = 18 + \frac{13}{24} = 18\frac{13}{24}$$

Ответ:

1) $$11\frac{3}{8}$$

2) $$15\frac{23}{40}$$

3) $$8\frac{29}{96}$$

4) $$18\frac{13}{24}$$