Решите систему неравенств: 9x-7<0; 16/(36x^2-25)<0.

\[\left\{ \begin{matrix}
9x - 7 < 0\ \ \ \ \ \ \ \\
\frac{16}{36x^{2} - 25} < 0 \\
\end{matrix} \right.\ \text{\ \ \ \ \ \ \ }\]

\[\left\{ \begin{matrix}
x < \frac{7}{9}\text{\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ } \\
36x^{2} - 25 < 0 \\
\end{matrix} \right.\ \text{\ \ \ \ \ \ \ }\]

\[\left\{ \begin{matrix}
x < \frac{7}{9}\text{\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ } \\
(6x - 5)(6x + 5) < 0 \\
\end{matrix} \right.\ \]

\[\left\{ \begin{matrix}
x < \frac{7}{9}\text{\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ } \\
36 \cdot \left( x - \frac{5}{6} \right)\left( x + \frac{5}{6} \right) < 0 \\
\end{matrix} \right.\ \]

\[Ответ:\ \ \left( - \frac{5}{6};\frac{7}{9} \right).\]