Решите систему неравенств: (x^2-36)/(3x^2+0,5)<0; (2x-14)/(x^2+2x-35)<0.

\[\Longrightarrow \left\{ \begin{matrix}
x^{2} - 36 > 0\ \ \ \ \ \ \ \ \ \ \ \ \ \\
\frac{2 \cdot (x - 7)}{(x + 7)(x - 5)} < 0 \\
\end{matrix} \right.\ \text{\ \ \ \ \ \ \ \ }\]

\[\left\{ \begin{matrix}
(x - 6)(x + 6) > 0 \\
\frac{2 \cdot (x - 7)}{(x + 7)(x - 5)} < 0 \\
\end{matrix} \right.\ \]

\[Ответ:(5;6).\]