{log2x + log2y = 2
x - 4y = 15
{log2(xy) = 2
x - 4y = 15
{xy = 4
x - 4y = 15
{x = 4/y
4/y - 4y = 15
{x = 4/y
4 - 4y2 = 15y
4y2 + 15y - 4 = 0
D = 225 + 64 = 289
y1 = (-15 + 17)/8 = 0,25
y2 = (-15 - 17)/8 = -4
x1 = 4/0,25 = 16
x2 = 4/(-4) = -1
Подставим х и у в систему:
log216 + log20,25 = 4 - 2 = 2
16 - 4*0,25 = 16 - 1 = 15
log2(-1) + log2(-4) - не имеет смысла
-1 - 4*(-4) = -1 + 16 = 15
Ответ: (16; 0,25)