Решите систему уравнений 2*(3x-y)-5=2x-3y; 5-(x-2y)=4y+16.

\[\left\{ \begin{matrix}
2 \cdot (3x - y) - 5 = 2x - 3y \\
5 - (x - 2y) = 4y + 16\ \ \ \ \ \ \\
\end{matrix} \right.\ \]

\[\left\{ \begin{matrix}
6x - 2y - 5 = 2x - 3y \\
5 - x + 2y = 4y + 16\ \ \\
\end{matrix} \right.\ \]

\[\left\{ \begin{matrix}
4x + y = 5\ \ \ \ \ \ \\
x + 2y = - 11 \\
\end{matrix} \right.\ \text{\ \ \ \ \ \ }\]

\[\left\{ \begin{matrix}
y = 5 - 4x\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \\
x + 2 \cdot (5 - 4x) = - 11 \\
\end{matrix} \right.\ \]

\[\left\{ \begin{matrix}
y = 5 - 4x\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \\
x + 10 - 8x = - 11 \\
\end{matrix} \right.\ \text{\ \ \ \ \ \ \ }\left\{ \begin{matrix}
y = 5 - 4x\ \ \\
- 7x = - 21 \\
\end{matrix} \right.\ \]

\[\left\{ \begin{matrix}
x = 3\ \ \ \ \ \ \ \ \ \ \ \ \ \ \\
y = 5 - 4 \cdot 3 \\
\end{matrix} \right.\ \text{\ \ \ \ \ \ \ }\left\{ \begin{matrix}
x = 3\ \ \ \\
y = - 7 \\
\end{matrix} \right.\ \]

\[Ответ:(3;\ - 7).\]