Решите систему уравнений: 6(x-3)=7y-1; 2(y+6)=3x+2.

\[\left\{ \begin{matrix}
6(x - 3) = 7y - 1 \\
2(y + 6) = 3x + 2 \\
\end{matrix} \right.\ \text{\ \ \ \ \ \ \ }\]

\[\left\{ \begin{matrix}
6x - 18 = 7y - 1 \\
2y + 12 = 3x + 2 \\
\end{matrix} \right.\ \text{\ \ \ \ \ }\]

\[\left\{ \begin{matrix}
6x - 7y = 17\ \ \ \ \ \ \ \ \ \ \ \\
3x - 2y = 10\ | \cdot 2\ \\
\end{matrix} \right.\ \]

\[\left\{ \begin{matrix}
6x - 7y = 17 \\
6x - 4y = 20 \\
\end{matrix} \right.\ - \ \ \ \ \ \]

\[\left\{ \begin{matrix}
- 3y = - 3\ \ \ \ \\
x = \frac{20 + 4y}{6} \\
\end{matrix} \right.\ \text{\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ }\]

\[\left\{ \begin{matrix}
y = 1 \\
x = 4 \\
\end{matrix} \right.\ \]

\[Ответ:(4;1).\]