Решите систему уравнений: x-6y=20; 4x+2y=2.

\[\left\{ \begin{matrix}
x - 6y = 20\ \ \ \ | \cdot 2 \\
4x + 2y = 2\ \ \ |\ :2 \\
\end{matrix} \right.\ \text{\ \ \ \ \ \ \ \ \ }\]

\[\left\{ \begin{matrix}
2x - 12y = 40 \\
2x + y = 1\ \ \ \ \ \ \ \\
\end{matrix} \right.\ ( - )\]

\[- 13y = 39\]

\[y = - 3.\]

\[\left\{ \begin{matrix}
x = 20 + 6y \\
y = - 3\ \ \ \ \ \ \ \ \ \ \\
\end{matrix} \right.\ \text{\ \ \ \ \ \ \ \ \ }\left\{ \begin{matrix}
y = - 3\ \ \ \ \ \ \ \ \ \ \\
x = 20 - 18 \\
\end{matrix} \right.\ \text{\ \ \ \ \ \ \ \ \ }\]

\[\left\{ \begin{matrix}
y = - 3 \\
x = 2\ \ \ \\
\end{matrix} \right.\ \]

\[Ответ:(2;\ - 3).\]