\[\left\{ \begin{matrix}
2x + 3y = - 1\ \ \ | \cdot ( - 3) \\
3x + 5y = - 2\ \ \ | \cdot (2)\text{\ \ \ \ } \\
\end{matrix} \right.\ \text{\ \ \ \ \ }\]
\[\left\{ \begin{matrix}
- 6x - 9y = 3\ \ \ \ \ (1) \\
6x + 10y = - 4\ \ \ (2) \\
\end{matrix} \right.\ \]
\[(1) + (2) \Longrightarrow y = - 1\]
\[\left\{ \begin{matrix}
y = - 1\ \ \ \ \ \ \ \ \ \ \ \ \\
2x + 3y = - 1 \\
\end{matrix} \right.\ \text{\ \ \ \ \ \ }\]
\[\left\{ \begin{matrix}
y = - 1\ \ \ \ \ \ \ \ \ \ \ \ \ \\
2x = - 1 - 3y \\
\end{matrix} \right.\ \text{\ \ \ \ \ \ }\]
\[\left\{ \begin{matrix}
y = - 1\ \ \ \ \ \ \ \ \\
x = - \frac{1}{2} + \frac{3}{2} \\
\end{matrix} \right.\ \text{\ \ \ \ \ }\]
\[\left\{ \begin{matrix}
y = - 1 \\
x = 1\ \ \\
\end{matrix} \right.\ \]
\[Ответ:(1;\ - 1).\]