142. Решите уравнение:
1) \( (4 - 5x)(16 + 20x + 25x^2) + 5x(5x-2)(5x + 2) = 4 \)
\( 64 - 125x^3 + 5x(25x^2 - 4) = 4 \)
\( 64 - 125x^3 + 125x^3 - 20x = 4 \)
\( 64 - 20x = 4 \)
\( -20x = -60 \)
\( x = 3 \)
2) \( 81(\frac{1}{3}x - 1)(\frac{1}{9}x^2 + \frac{1}{3}x + 1) -3x(x - 2)^2 = 12x^2 \)
\( 81(\frac{1}{27}x^3 - 1) - 3x(x^2 - 4x + 4) = 12x^2 \)
\( 3x^3 - 81 - 3x^3 + 12x^2 - 12x = 12x^2 \)
\( -81 - 12x = 0 \)
\( -12x = 81 \)
\( x = -\frac{81}{12} = -\frac{27}{4} \)