Решите уравнение: 1) 3x = 36-x; 2) 13x+24=9x;

Решение:

1. 1) \( 3x = 36 - x \)
   \( 3x + x = 36 \)
   \( 4x = 36 \)
   \( x = \frac{36}{4} \)
   \( x = 9 \)
2. 2) \( 13x + 24 = 9x \)
   \( 13x - 9x = -24 \)
   \( 4x = -24 \)
   \( x = \frac{-24}{4} \)
   \( x = -6 \)

Ответ: 1) \( x = 9 \); 2) \( x = -6 \).