Решите уравнение: 1) 4x = 24 + x; 2) 10x+28=3x;

Решение:

1. 1) \( 4x = 24 + x \)
   \( 4x - x = 24 \)
   \( 3x = 24 \)
   \( x = \frac{24}{3} \)
   \( x = 8 \)
2. 2) \( 10x + 28 = 3x \)
   \( 10x - 3x = -28 \)
   \( 7x = -28 \)
   \( x = \frac{-28}{7} \)
   \( x = -4 \)

Ответ: 1) \( x = 8 \); 2) \( x = -4 \).