Решите уравнение: 2x^3+4x^2=8(x+2).

\[2x^{3} + 4x^{2} = 8(x + 2)\]

\[2x^{2}(x + 2) - 8(x + 2) = 0\]

\[(x + 2)\left( 2x^{2} - 8 \right) = 0\]

\[2(x + 2)\left( x^{2} - 4 \right) = 0\]

\[2(x + 2)(x - 2)(x + 2) = 0\]

\[x = \pm 2.\]