Решите уравнение: 3x^3+6x^2=12x+24.

\[3x^{3} + 6x^{2} = 12x + 24\]

\[3x^{2}(x + 2) = 12(x + 2)\]

\[3x^{2}(x + 2) - 12(x + 2) = 0\]

\[(x + 2)\left( 3x^{2} - 12 \right) = 0\]

\[3(x + 2)\left( x^{2} - 4 \right) = 0\]

\[3(x + 2)(x - 2)(x + 2) = 0\]

\[x = \pm 2.\]