Решите уравнение: 2(x-2)(x+2)=(x-4)(x+4)+(x-3)(x+3)+x.

\[2(x - 2)(x + 2) = (x - 4)(x + 4) + (x - 3)(x + 3) + x\]

\[2\left( x^{2} - 4 \right) = x^{2} - 16 + x^{2} - 9 + x\]

\[2x^{2} - 8 = 2x^{2} + x - 25\]

\[x = 13.\]