Решите уравнение: 3(x+1)(x-1)=2(x-2)(x+2)+x^2+2x.

\[3(x + 1)(x - 1) = 2(x - 2)(x + 2) + x^{2} + 2x\]

\[3\left( x^{2} - 1 \right) = 2\left( x^{2} - 4 \right) + x^{2} + 2x\]

\[3x^{2} - 3 = 2x^{2} - 8x + x^{2} + 2x\]

\[6x = 3\]

\[x = \frac{3}{6} = 0,5.\]