Решите уравнение: (3x+4)^2-16=0.

\[(3x + 4)^{2} - 16 = 0\]

\[(3x + 4 - 4)(3x + 4 + 4) = 0\]

\[3x(3x + 8) = 0\]

\[3x = 0\]

\[x = 0.\]

\[3x + 8 = 0\]

\[3x = - 8\]

\[x = - \frac{8}{3} = - 2\frac{2}{3}.\]

\[Ответ:x = - 2\frac{2}{3};x = 0.\]