Решите уравнение 4x(x+3)=4-3x.

\[4x(x + 3) = 4 - 3x\]

\[4x^{2} + 12x - 4 + 3x = 0\]

\[4x^{2} + 15x - 4 = 0\]

\[D = 225 + 64 = 289\]

\[x_{1} = \frac{- 15 + 17}{8} = \frac{2}{8} = \frac{1}{4} = 0,25;\]

\[x_{2} = \frac{- 15 - 17}{8} = - \frac{32}{8} = - 4.\]

\[Ответ:\ - 4;0,25.\]