Решите уравнение: 8x^2+6x=0.

\[8x^{2} + 6x = 0\]

\[2x \cdot (4x + 3) = 0\]

\[x = 0,\ \ 4x = - 3\]

\[\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x = - \frac{3}{4}\]

\[Ответ:x = 0;\ x = - \frac{3}{4}\text{.\ }\]