Решите уравнение: (9x^4)^5*(3x)^3/(27x^5)^4=-192.

\[\frac{\left( 9x^{4} \right)^{5} \bullet (3x)^{3}}{\left( 27x^{5} \right)^{4}} = - 192\]

\[\frac{3^{10} \bullet 3^{3}x^{3}}{3^{12}} = - 192\]

\[\frac{3^{13}x^{3}}{3^{12}} = - 192\]

\[3x³ = - 192\ \ \ \ \ |\ :3\]

\[x^{3} = - 64\]

\[x = - 4.\]