Решите уравнение: a) (x - 3)² – x² = 15; б) (4x + 3)² - 8x(2x + 5) = 1.

a) \[(x - 3)^2 - x^2 = 15\] \[x^2 - 6x + 9 - x^2 = 15\] \[-6x = 15 - 9\] \[-6x = 6\] \[x = -1\] б) \[(4x + 3)^2 - 8x(2x + 5) = 1\] \[16x^2 + 24x + 9 - 16x^2 - 40x = 1\] \[-16x = 1 - 9\] \[-16x = -8\] \[x = \frac{-8}{-16}\] \[x = \frac{1}{2}\] Ответы: а) \(x = -1\); б) \(x = \frac{1}{2}\).