Решите уравнение: (x^2+8x)/(x+10)=20/(x+10).

\[\frac{x^{2} + 8x}{x + 10} = \frac{20}{x + 10}\]

\[\frac{x^{2} + 8x}{x + 10} - \frac{20}{x + 10} = 0\]

\[\frac{x^{2} + 8x - 20}{x + 10} = 0,\ \ x \neq - 10\]

\[x² + 8x - 20 = 0\]

\[x_{1} + x_{2} = - 8\]

\[x_{1} \cdot x_{2} = - 20\]

\[Ответ:x = 2.\]