Вопрос:

4. Решите уравнение: 1) 2x³ - 32x = 0; 2) 81x³ + 18x² + x = 0; 3) x³ + 6x2 - x - 6 = 0.

Ответ:

1) $$2x^3 - 32x = 0$$
$$2x(x^2 - 16) = 0$$
$$2x(x - 4)(x + 4) = 0$$
$$x = 0, x = 4, x = -4$$

Ответ: x = 0, x = 4, x = -4

2) $$81x^3 + 18x^2 + x = 0$$
$$x(81x^2 + 18x + 1) = 0$$
$$x(9x + 1)^2 = 0$$
$$x = 0, x = -\frac{1}{9}$$

Ответ: x = 0, x = -1/9

3) $$x^3 + 6x^2 - x - 6 = 0$$
$$x^2(x + 6) - (x + 6) = 0$$
$$(x^2 - 1)(x + 6) = 0$$
$$(x - 1)(x + 1)(x + 6) = 0$$
$$x = 1, x = -1, x = -6$$

Ответ: x = 1, x = -1, x = -6