Решение:
а) \(-4x + 5,9 = -6,3\)
\(-4x = -6,3 - 5,9\)
\(-4x = -12,2\)
\(x = \frac{-12,2}{-4} = 3,05\)
б) \(-2 \frac{2}{5} \cdot (\frac{3}{8}x + \frac{1}{4}) = 4,5\)
\(-\frac{12}{5} \cdot (\frac{3}{8}x + \frac{1}{4}) = \frac{9}{2}\)
\(\frac{3}{8}x + \frac{1}{4} = \frac{9}{2} : (-\frac{12}{5})\)
\(\frac{3}{8}x + \frac{1}{4} = \frac{9}{2} \cdot (-\frac{5}{12})\)
\(\frac{3}{8}x + \frac{1}{4} = -\frac{3 \cdot 3 \cdot 5}{2 \cdot 3 \cdot 4} = -\frac{15}{8}\)
\(\frac{3}{8}x = -\frac{15}{8} - \frac{1}{4} = -\frac{15}{8} - \frac{2}{8} = -\frac{17}{8}\)
\(x = -\frac{17}{8} : \frac{3}{8} = -\frac{17}{8} \cdot \frac{8}{3} = -\frac{17}{3} = -5 \frac{2}{3}\)