132. Решите уравнение. x+\frac{4}{7}=\frac{9}{14} 2) (x-\frac{17}{36})=\frac{9}{40} 3) 2\frac{3}{4}-(x-3\frac{1}{8})=1\frac{1}{6} 133. Выполните действия. 1) 6\frac{1}{15}-2\frac{1}{9}+1\frac{3}{10}= 2) 7\frac{5}{8}-5\frac{2}{36}+3\frac{3}{8}= 3) 10\frac{9}{22}-3\frac{11}{11}-4\frac{8}{33}= 4) 12\frac{5}{12}-(3\frac{1}{4}+1)= 5) 15-(6\frac{4}{35}-2\frac{3}{14})= 139. Найдите значение выражения, выбирая удобный порядок вычислений. 1) (7\frac{5}{19}+3\frac{7}{24})-4\frac{5}{19}+\frac{3}{24}= 2) (13\frac{2}{17}+6\frac{9}{35})-5\frac{12}{35}= 3) 12\frac{11}{21}-(3\frac{2}{13}+8\frac{11}{21})=

132. Решите уравнение.

1) $$x+\frac{4}{7}=\frac{9}{14}$$

$$x = \frac{9}{14} - \frac{4}{7}$$

$$x = \frac{9}{14} - \frac{8}{14}$$

$$\mathbf{x = \frac{1}{14}}$$

2) $$(x-\frac{17}{36})=\frac{9}{40}$$

$$x = \frac{9}{40} + \frac{17}{36}$$

$$x = \frac{9 \cdot 9}{40 \cdot 9} + \frac{17 \cdot 10}{36 \cdot 10}$$

$$x = \frac{81}{360} + \frac{170}{360}$$

$$x = \frac{251}{360}$$

$$\mathbf{x = \frac{251}{360}}$$

3) $$2\frac{3}{4}-(x-3\frac{1}{8})=1\frac{1}{6}$$

$$\frac{11}{4} - (x - \frac{25}{8}) = \frac{7}{6}$$

$$\frac{11}{4} - x + \frac{25}{8} = \frac{7}{6}$$

$$\frac{22}{8} + \frac{25}{8} - x = \frac{7}{6}$$

$$\frac{47}{8} - x = \frac{7}{6}$$

$$x = \frac{47}{8} - \frac{7}{6}$$

$$x = \frac{47 \cdot 3}{8 \cdot 3} - \frac{7 \cdot 4}{6 \cdot 4}$$

$$x = \frac{141}{24} - \frac{28}{24}$$

$$x = \frac{113}{24}$$

$$\mathbf{x = 4\frac{17}{24}}$$

133. Выполните действия.

1) $$6\frac{1}{15}-2\frac{1}{9}+1\frac{3}{10}=$$

$$\frac{91}{15}-\frac{19}{9}+\frac{13}{10}=$$

$$\frac{91 \cdot 6}{15 \cdot 6}-\frac{19 \cdot 10}{9 \cdot 10}+\frac{13 \cdot 9}{10 \cdot 9}=$$

$$\frac{546}{90}-\frac{190}{90}+\frac{117}{90}=$$

$$\frac{546-190+117}{90}=\frac{473}{90}=5\frac{23}{90}$$

$$\mathbf{=5\frac{23}{90}}$$

2) $$7\frac{5}{8}-5\frac{2}{36}+3\frac{3}{8}=$$

$$7\frac{5}{8}+3\frac{3}{8}-5\frac{2}{36}=$$

$$10\frac{8}{8}-5\frac{2}{36}=$$

$$11-5\frac{1}{18}=$$

$$10\frac{18}{18}-5\frac{1}{18}=5\frac{17}{18}$$

$$\mathbf{=5\frac{17}{18}}$$

3) $$10\frac{9}{22}-3\frac{11}{11}-4\frac{8}{33}=$$

$$10\frac{9}{22}-4-4\frac{8}{33}=$$

$$6\frac{9}{22}-4\frac{8}{33}=$$

$$6\frac{27}{66}-4\frac{16}{66}=2\frac{11}{66}=2\frac{1}{6}$$

$$\mathbf{=2\frac{1}{6}}$$

4) $$12\frac{5}{12}-(3\frac{1}{4}+1)=$$

$$12\frac{5}{12}-4\frac{1}{4}=$$

$$12\frac{5}{12}-4\frac{3}{12}=8\frac{2}{12}=8\frac{1}{6}$$

$$\mathbf{=8\frac{1}{6}}$$

5) $$15-(6\frac{4}{35}-2\frac{3}{14})=$$

$$15-(6\frac{8}{70}-2\frac{15}{70})=$$

$$15-(4\frac{-7}{70})=$$

$$15-(3\frac{63}{70})=15-3\frac{9}{10}=14\frac{10}{10}-3\frac{9}{10}=11\frac{1}{10}$$

$$\mathbf{=11\frac{1}{10}}$$

139. Найдите значение выражения, выбирая удобный порядок вычислений.

1) $$(7\frac{5}{19}+3\frac{7}{24})-4\frac{5}{19}+\frac{3}{24}=$$

$$7\frac{5}{19}-4\frac{5}{19}+3\frac{7}{24}+\frac{3}{24}=$$

$$3+3\frac{10}{24}=6\frac{5}{12}$$

$$\mathbf{=6\frac{5}{12}}$$

2) $$(13\frac{2}{17}+6\frac{9}{35})-5\frac{12}{35}=$$

$$13\frac{2}{17}+(6\frac{9}{35}-5\frac{12}{35})=$$

$$13\frac{2}{17}+\frac{35 \cdot 6+9-35 \cdot 5-12}{35}=$$

$$13\frac{2}{17}+\frac{219-187}{35}=13\frac{2}{17}+\frac{32}{35}=13\frac{2 \cdot 35+32 \cdot 17}{17 \cdot 35}=13\frac{70+544}{595}=13\frac{614}{595}=14\frac{19}{595}$$

$$\mathbf{=14\frac{19}{595}}$$

3) $$12\frac{11}{21}-(3\frac{2}{13}+8\frac{11}{21})=$$

$$12\frac{11}{21}-8\frac{11}{21}-3\frac{2}{13}=4-3\frac{2}{13}=3\frac{13}{13}-3\frac{2}{13}=\frac{11}{13}$$

$$\mathbf{=\frac{11}{13}}$$