а) \(x=-3\frac{5}{12}+11\frac{4}{9}=\frac{-41}{12}+\frac{103}{9}=\frac{165}{36}=4\frac{7}{12}\).
б) \(x=\left(-2\frac{7}{19}\right)\cdot1\frac{4}{15}=\left(-\frac{45}{19}\right)\cdot\frac{19}{15}=-3\).
в) \(x=\left(-2\frac{2}{11}\right):\left(-1\frac{5}{6}\right)=\left(-\frac{24}{11}\right):\left(-\frac{11}{6}\right)=\frac{144}{121}=1\frac{23}{121}\).
Ответ: а) \(4\frac{7}{12}\); б) \(-3\); в) \(1\frac{23}{121}\).