Решите уравнения-пропорции: \(\frac{3}{x} = 8\), \(\frac{4x}{3} = \frac{1}{6}\), \(\frac{3}{2} = \frac{7}{x}\)

Решение:

1. \(\frac{3}{x} = 8\)

1. Крест-накрест: \( 3 \cdot 1 = 8 \cdot x \)
2. \( 3 = 8x \)
3. \( x = \frac{3}{8} \)

2. \(\frac{4x}{3} = \frac{1}{6}\)

1. Крест-накрест: \( 4x \cdot 6 = 3 \cdot 1 \)
2. \( 24x = 3 \)
3. \( x = \frac{3}{24} = \frac{1}{8} \)

3. \(\frac{3}{2} = \frac{7}{x}\)

1. Крест-накрест: \( 3 \cdot x = 2 \cdot 7 \)
2. \( 3x = 14 \)
3. \( x = \frac{14}{3} \)

Ответ: \(x = \frac{3}{8}\), \(x = \frac{1}{8}\), \(x = \frac{14}{3}\).